Graphing Parabolas
This is a circle of radius 4 centred at the origin Given x^2y^2=16 Note that we can rewrite this equation as (x0)^2(y0)^2 = 4^2 This is in the standard form (xh)^2(yk)^2 = r^2 of a circle with centre (h, k) = (0, 0) and radius r = 4 So this is a circle of radius 4 centred at the origin graph{x^2y^2 = 16 10, 10, 5, 5}Y 2 z = 0 Solution Traces in x= kare y2 z2 = 9k2, family of hyperbolas for k6= 0 and intersecting lines for k= 0 Traces in y= kare 9x2 z2 = k2;K 0, family of ellpises, traces in z= kare y2 9z2 = k2 again ellipses for k6= 0 Graph is an elliptic cone with axis the yaxis, vertex origin 2) Consider the equation y 2= x 4z2 4 Reduce to
